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zwa197359

我相信大家都下载过“各种滑块设计的注意事项”，其中有几处我有些疑问，现和大家讨论一下。在“滑块抽芯方向与分型面成交角的关系为滑块抽向动模”中α°=d°-b°应为α°=d°+b°；在“双”T”槽的计算公式及注意事项”中A>A1但图上A却比A1小很多,还有就是β角该如何定?

zwa197359

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<P 2.8? mso-char-indent-count: 125%; LINE-HEIGHT: 39.2pt; TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm><FONT face="Times New Roman">1.</FONT>滑块抽芯方向与分型面成交角的关系为滑块抽向动模<FONT face="Times New Roman">.

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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 2.0? 28pt;>如下图所示：
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;>
<P><FONT face="Times New Roman"></FONT></P>
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;>
<P><FONT face="Times New Roman"></FONT></P>
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;>
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;>
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;>
<P><FONT face="Times New Roman"></FONT></P>
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;>
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;>α°<FONT face="Times New Roman">=d</FONT>°<FONT face="Times New Roman">-b</FONT>°
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;><FONT face="Times New Roman">d</FONT>°<FONT face="Times New Roman">+b</FONT>°≦<FONT face="Times New Roman">25</FONT>°
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;><FONT face="Times New Roman">c</FONT>°<FONT face="Times New Roman">=</FONT>α°<FONT face="Times New Roman">+(2</FONT>°<FONT face="Times New Roman">-3</FONT>°<FONT face="Times New Roman">)
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;><FONT face="Times New Roman">H=H1-S*sinb</FONT>°
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;><FONT face="Times New Roman">S=H1*tgd</FONT>°<FONT face="Times New Roman">/cosb</FONT>°
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;><FONT face="Times New Roman">L4=H1/cosd</FONT>°
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<p>[upload=bmp]NewUploadFile/2004-9/200492319616846.bmp[/img]

[此贴子已经被作者于2004-9-23 19:06:18编辑过]

zwa197359

<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 1.0? 14pt;><FONT face="Times New Roman">4)</FONT>双<FONT face="Times New Roman">”T”</FONT>槽的计算公式及注意事项：


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<P><FONT face="Times New Roman"></FONT></P>
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<P LINE-HEIGHT: char; LAYOUT-GRID-MODE: 0pt; 0cm 125%?>
<P><FONT face="Times New Roman"></FONT></P>
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<P LINE-HEIGHT: char; LAYOUT-GRID-MODE: 0pt; 0cm 125%?>
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<P LINE-HEIGHT: char; LAYOUT-GRID-MODE: 0pt; 0cm 125%?>
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<P LINE-HEIGHT: char; LAYOUT-GRID-MODE: 0pt; 0cm 125%?>
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<P LINE-HEIGHT: char; LAYOUT-GRID-MODE: 0pt; 0cm 125%?>
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<P LINE-HEIGHT: char; LAYOUT-GRID-MODE: 0pt; 0cm 125%?>
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<P LINE-HEIGHT: char; LAYOUT-GRID-MODE: 0pt; 0cm 125%?>
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<P LINE-HEIGHT: char; LAYOUT-GRID-MODE: 0pt; 0cm 125%?>
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<P LINE-HEIGHT: char; LAYOUT-GRID-MODE: 0pt; 0cm 125%?>
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<P LINE-HEIGHT: char; LAYOUT-GRID-MODE: 0pt; 0cm 125%?>
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<p><BR clear=all vglayout?>
<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 1.0? 14pt;>如上图中
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0cm -.01gd? mso-para-margin-left: 2.92; 40.9pt; -0.1pt; 0pt>S3=H*tgγ;   
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0cm -.01gd? mso-para-margin-left: -0.1pt; 0pt 3.92; 54.9pt;>(H为滑块下降的高度即小拉杆行程; γ为拨块角度)
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0cm -.01gd? mso-para-margin-left: 2.92; 40.9pt; -0.1pt; 0pt>S2=δ2*cosγ；   
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0cm -.01gd? mso-para-margin-left: -0.1pt; 0pt 3.92; 54.9pt;>(δ2为拨块与滑块间隙，一般为0.5mm)
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0cm -.01gd? mso-para-margin-left: 2.92; 40.9pt; -0.1pt; 0pt>S=S3-S2=H*tgγ-δ2*cosγ=(H*sinγ-δ2)/cosγ；
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0cm -.01gd? mso-para-margin-left: 2.92; 40.9pt; -0.1pt; 0pt>　(S为滑块水平运动距离)
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0cm -.01gd? mso-para-margin-left: 2.92; 40.9pt; -0.1pt; 0pt>S4=δ1/cosα;  
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0cm -.01gd? mso-para-margin-left: -0.1pt; 0pt 3.92; 54.9pt;>(δ1滑块入子与滑块间隙隙；α为滑块入子倾斜角度)
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<P LINE-HEIGHT: char; LAYOUT-GRID-MODE: 0pt; 0cm 125%?>　　　S1=(H*sinβ-δ1)/sin(α+β)；　
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 4.0? 56pt;>（β为勾槽间隙，一般为0.5mm；S1为滑块入子脱离倒勾距离）
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 1.0? 14pt;>注意事项：
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<P LINE-HEIGHT: char; LAYOUT-GRID-MODE: 0cm 125%? 0pt 42.1pt;>a.装配要求：滑块入子与倾斜的入子孔装配，要特别注意尺寸A与A1的关系，
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 9.0? 126pt;>应为A&gt;A1 。
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<P mso-char-indent-count: 125%; LINE-HEIGHT: TEXT-INDENT: char; LAYOUT-GRID-MODE: 0pt; 0cm 3.0? 42pt;><FONT face="Times New Roman">b.</FONT>双<FONT face="Times New Roman">T</FONT>槽公差：如下图
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<p>[upload=bmp]NewUploadFile/2004-9/2004923191018108.bmp[/img]

[此贴子已经被作者于2004-9-23 19:11:54编辑过]

zjliu_163

不太懂，但我还顶